Dikazahn Anyway, I tried with smaller voltage and it functions well using 2N in Multisim. How about the VGSS.? Replacing a 4 pin leaded inductor with a 2 pin Started by gkmaia Yesterday at Am I on the right track now.? According to the simulation, the V DS of Q1 and Q4 is too large and only less than half of the voltage fall across R1.

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Mazuran I understand it finally. The value of R1 is 5Ohm. This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register. I knew there was something I had missed. According to the simulation, the V DS of Q1 and Q4 is too large and datasueet less than half of the voltage fall across R1. That will just give you the resistance when it starts, the running resistance will be a lot higher. Due to the lag in the Logic Gates. The resistance is some function of the gate-source — for a given Vgs, the mosfet will act like a very small value resistor, up to some current limit when it enters saturationand starts acting like a current source dztasheet dissipating a lot of power.

You must log in or register to reply here. Did anyone else look at the specs on those parts? I did not capture the voltage of V GS but it is already close to V and that is the max it can go. The resistance R DS at that time would be somewhere near mOhm 0. This is also very efficient because it also has no chance of shooting thru.

How would I make the Source voltage become 20V.? First Prev 2 of 3 Go to page. Did i understand correctly.? Potentiometer Questions Started by norbss Yesterday at Is that what you have been trying to say Hero? For fast switching times, you want to be able to discharge the input capacitance as quickly as possible; you can buy special driver ICs for this. Welcome to our site! Click here to register now. Lets say V D at that time is 30V. Related Articles


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